20n^2=15n

Solution for 20n^2=15n equation:

20n^2=15n

We move all terms to the left:

20n^2-(15n)=0

a = 20; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·20·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*20}=\frac{0}{40}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*20}=\frac{30}{40}
=3/4
$